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## Homework Statement

A ball (0.45kg) is kicked at 32m/s, 45° above the horizontal. If the average force of air resistance is

1N, how far will it go?

## Homework Equations

so I figure you would need energy to solve this question but I'm having trouble finding the total distance it travels, not just the horizontal distance but the parabolic-like distance. Am I on the right track? I have some of the things figured out but I'm finding it a little overwhelming.

## The Attempt at a Solution

Loss to friction W=Fd W=(1)d

E

_{p}=mgh=mgd

_{y}=(0.45)(9.8)d

_{y}for potential energy at maximum

E

_{k}=1/2(0.45)(32)

^{2}for kinetic energy at start

Y direction

V

_{o}= 32 sin 45°= 22.63m/s

V=?

to find acceleration (this could be wrong) F=ma= 1=0.45a which means a=2.22 but the y component =1.57+g=11.37 down

d

_{y}=?

t=?

X direction

V

_{o}= 22.63m/s

V=?

Did the same thing to find a here

a=-1.57

d

_{x}=?

t=?